Zad 1 str 80
Oblicz pole kwadratu o boku:
a) 23 cm
b) 2,5 dm
c) 10,7 m
d) 8 1/4 cm
P=a*a
23*23=529cm^2
2,5*2,5=6,25dm^2
10,7*10,7=114,49m^2
8 1/4*8 1/4=68,0625cm^2
P= a^2
23^2 = 23cm*23cm = 529 cm^2
2,5^2 = 2,5dm*2,5dm = 6,25 dm^2
10^2 = 10,7m*10,7m = 114,49 m^2
d) 8 1/4 cm = 8,25 cm
(8,25)^2 = 8,25cm*8,25cm = 68,0625 cm^2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=a*a
23*23=529cm^2
2,5*2,5=6,25dm^2
10,7*10,7=114,49m^2
8 1/4*8 1/4=68,0625cm^2
a) 23 cm
P= a^2
23^2 = 23cm*23cm = 529 cm^2
b) 2,5 dm
2,5^2 = 2,5dm*2,5dm = 6,25 dm^2
c) 10,7 m
10^2 = 10,7m*10,7m = 114,49 m^2
d) 8 1/4 cm = 8,25 cm
(8,25)^2 = 8,25cm*8,25cm = 68,0625 cm^2