Proszę rozwiążcie daje naj (4,3-1,1)*2*3/4-1.... Question from @alisonobi2000

June 2022 2 3 Report

Proszę rozwiążcie daje naj (4,3-1,1)*2*3/4-1

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$(4,3-1,1)\cdot2\cdot\frac{3}{4}-1=\\\\=3,2\cdot2\cdot\frac{3}{4}-1=6,4\cdot\frac{3}{4}-1=\\\\=1,6\cdot3-1=4,8-1=\boxed{3,8}$

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gosiagraza

Odpowiedź:

(4,3 - 1.1) * 2 * 3/4 - 1 = 3,2 * 2 * 3/4 - 1 = 6,4 * 3/4 - 1 = 6,4 * 0,75 - 1 = 4,8 - 1 = 3,8

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