rozwiaż równanie i delte.
zad 1
a)(x-3)2 = 25
b)4*(3x+2)2 = 8
c)1/3*(6-5x)2 = 0
d)(0,2x-3)2 =-1,4
e)-3*(5x+1/2)2 =2
f)-0,3*(0,7x+1)2 =-6
g)x2 - 4x+1 = 0
h)x2+6x-7 = 0
i)x2+3x-2,85=0
zad 2
a)x2-5x-14 = 0
b)-x2-2x+15 = 0
c) -4x2+2x-5=0
d)x2+10=7x
e)1+x+5x2=0
f)185-3x2-4x=0
g)12x+7=21x2
h)0,04x2-0,4x=1
i)4x-3x2=1 1/3
zad 3
a)2x2-7=0
b)x*(5-2x)=0
c)(x-3)(2x+1)=0
d)x-3x2 =0
e)x2-2x+1 =0
f)(3x-1)2 =0
błagam was pomózcie mi.
te zadania to dla mnie smierc i życie
no i dam najj :)
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Δ=b²-4ac
Δ>0 , 2 miejsca zerowe : x1=(-b-√Δ)/2a , x2=(-b+√Δ)/2a
Δ=0 , 1 m.z x=-b/2a
Δ<0 , 0 mz
1)
a)(x-3)2 = 25
x²-6x+9-25=0
x²-6x - 16 = 0
Δ=36 +64 = 100
√Δ=10
x1=(-b-√Δ)/2a = (6-10)/2 = -4/2=-2
x2=(-b+√Δ)/2a =(6+10)/2 = 16/2=8
b)4*(3x+2)2 = 8
4(9x²+12x+4) - 8 = 0
36x²+48x+16-8=0
36x²+48x+8=0
Δ=1296 - 1152 = 144
√Δ=12
x1=(-48-12)/72 = -60/72 = -5/6
x2=-36/72 = -1/2
c)1/3*(6-5x)2 = 0
1/3(36 - 60x + 25x²)=0
12 - 20x + 25/3x²=0
Δ=400-400 = 0
x=20: 2*(25/3) = 20 : 50/3 = 20* 3/50 = 60/50 = 6/5=1 1/5
d)(0,2x-3)2 =-1,4
0,04x²-1,2x+9 + 1,4 = 0
0,04x²-1,2x+10,4=0
Δ=1,44-1,664=-0,224
Δ<0 brak miejsc zerowych
e)-3*(5x+1/2)2 =2
-3(25x²+5x+1/4) - 2 = 0
-75x²-15x-3/4-2=0
-75x²-15x-11/4 = 0
Δ=225 - 225=0
x=-b/2a = 15/-150 = -1/10
f)-0,3*(0,7x+1)2 =-6
-0,3(0,49x²+1,4x+1)+6=0
-0,147x² - 0,42x +5,7=0
Δ=0,1764 + 3,3516=3,528
√Δ=√3,528
x1=(0,42-√3,528)/-0,294 =-(0,42-√3,528)/0,294
x2=(0,42+√3,528)/-0,294=-(0,42+√3,528)/0,294
g)x2 - 4x+1 = 0
Δ=16-4=12
√Δ=√12=2√3
x1=(4-2√3)/2 = 2(2-√3)/2 = 2-√3
x2=2+√3
h)x2+6x-7 = 0
Δ=36+28=64
√Δ=8
x1=(-6-8)/2 = -14/2=-7
x2=(-6+8)/2 = 2/2=1
i)x2+3x-2,85=0
Δ=9+11,4=20,4
√Δ=√20,4
x1=(-3-√20,4)/2
x2=(-3+√20,4)/2
zad 2
a)x2-5x-14 = 0
Δ=25+56=81
√Δ=9
x1=(5-9)/2=-4/2=-2
x2=(5+9)/2=14/2=7
b)-x2-2x+15 = 0
Δ=4+60=64
√Δ=8
x1=(2-8)/-2 = -6/-2=3
x2=(2+8)/-2=10/-2=-5
c) -4x2+2x-5=0
Δ=4-80=-76 <0 , brak rozwiązania
d)x2+10=7x
x²-7x+10=0
Δ=49-40=9
√Δ=3
x1=(7-3)/2 = 4/2=2
x2=(7+3)/2=10/2=5
e)1+x+5x2=0
Δ=1-20=-19 < 0 , brak rozwiązan
f)185-3x2-4x=0
-3x²-4x+185 = 0
Δ=16+2220=2236
√Δ=√2236 = 2√559
x1=(4-2√559)/-6 =2(2-√559)/-6 =- (2-√559)/3
x2=-(2+√559)/3
g)12x+7=21x2
-21x²+12x+7=0
Δ=144+588=732
√Δ=√732 = 2√183
x1=(-12-2√183)/-42 = -2(6+√183)/-42=-(6+√183)/21
x2=-(6-√183)/21
h)0,04x2-0,4x=1
0,04x²-0,4x-1=0
Δ=0,16+o,16=0,32
√Δ=√0,32=0,4√2
x1=(0,4-0,4√2)/0,08 = 0,4(1-√2)/0,08 = (1-√2)/0,2
x2=(1+√2)/0,2
i)4x-3x2=1 1/3
-3x²+4x-4/3 = 0
Δ=16-16=0
x=-4/-6=2/3
zad 3 )
a)2x2-7=0
2x²=7
x²=7/2
x=±√(7/2)
b)x*(5-2x)=0
x=0 U 5-2x=0
x=5/2
c)(x-3)(2x+1)=0
x=3 U x=-1/2
d)x-3x2 =0
x(1-3x)=0
x=0 U 1-3x=0
x=1/3
e)x2-2x+1 =0
(x-1)²=0
x-1=0
x=1
f)(3x-1)2 =0
3x-1=0
x=1/3