Question

Help me kk

1) dy / dx = [ xy² + 4y² ] / [ 3x²y - x² ]
mohon bantuannya kk please............................................


pers dif rensial dipisah

Answer 1

Dy/dx = (xy² + 4y²) / (3x²y - x²)
(3x²y - x²) dy/dx = (xy² + 4y²)
x²(3y - 1) dy/dx = y²(x + 4)
(3y - 1)/y² dy = (x + 4)/x² dx
3/y - 1/y² dy = 1/x + 4/x² dx
∫3/y - 1/y² dy = ∫1/x + 4/x² dx
3.lny + 1/y = lnx - 4/x + c
3.lny = lnx - 4/x + c - 1/y
lny = (lnx - 4/x + c - 1/y)/3
y = e^((lnx - 4/x + c - 1/y)/3)