podaj wzór funkcji f w postaci ogólnej jeśli a)f(x)=-2/3(x+9)(x-1) b)f(x)=4/3x(x+6)
a)
f(x) = ( -2/3)( x + 9)*(x - 1) = ( -2/3)*(x^2 - x + 9 x - 9) = ( -2/3)*(x^2 + 8 x - 9)
f(x) = ( -2/3) x^2 - (16/3) x + 6
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b)
f(x) = (4/3) x*( x + 6) = ( 4/3)*(x^2 + 6 x) = ( 4/3) x^2 + 8 x
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a)
f(x) = ( -2/3)( x + 9)*(x - 1) = ( -2/3)*(x^2 - x + 9 x - 9) = ( -2/3)*(x^2 + 8 x - 9)
f(x) = ( -2/3) x^2 - (16/3) x + 6
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b)
f(x) = (4/3) x*( x + 6) = ( 4/3)*(x^2 + 6 x) = ( 4/3) x^2 + 8 x
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