Rozwiąż równanie:
4[1/3(x+20)] = (x-20) + 2/3(x+20)
Daję naj . < 3
4[1x/3+20/3] = x-20 + 2x/3+ 40/3
4x/3+80/3 = x -20 + 2x/3 + 40/3 /*3
4x + 80 = 3x - 60 + 2x + 40
-x = -100 /:(-1)
x = 100
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4[1/3(x+20)] = (x-20) + 2/3(x+20)
4[1x/3+20/3] = x-20 + 2x/3+ 40/3
4x/3+80/3 = x -20 + 2x/3 + 40/3 /*3
4x + 80 = 3x - 60 + 2x + 40
-x = -100 /:(-1)
x = 100