Rozwiąż to równanie 4[1/3(x+20)]=(x-20)+2/3(x+20)
4[1/3(x+20)]=(x-20)+2/3(x+20)
4[1/3x+20/3]=x-20+2/3x+40/3
4/3x+80/3=x-20+2/3x+40/3
4/3x-2/3x-x=40/3-80/3-20
-1 2/3x=-33 1/3
x=20
4(=x-20++
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4[1/3(x+20)]=(x-20)+2/3(x+20)
4[1/3x+20/3]=x-20+2/3x+40/3
4/3x+80/3=x-20+2/3x+40/3
4/3x-2/3x-x=40/3-80/3-20
-1 2/3x=-33 1/3
x=20
4(=x-20++