Blagam rozwiazcie ze szczegolami!!!! 4[1/3(x+20)] = (x-20) + 2/3(x+20)
4[1/3(x+20)] = (x-20) + 2/3(x+20)
4[1/3x+20/3]=x-20+2/3x+40/3
4/3x+80/3=x-20+2/3x+40/3 /*3
3*4/3x+3*80/3=3*x-3*20+3*2/3x+3*40/3
4x+80=3x-60+2x+40
-x=-100 /:(-1)
x=100
-x=-100 /*(-1)
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4[1/3(x+20)] = (x-20) + 2/3(x+20)
4[1/3x+20/3]=x-20+2/3x+40/3
4/3x+80/3=x-20+2/3x+40/3 /*3
3*4/3x+3*80/3=3*x-3*20+3*2/3x+3*40/3
4x+80=3x-60+2x+40
-x=-100 /:(-1)
x=100
4[1/3(x+20)] = (x-20) + 2/3(x+20)
4[1/3x+20/3]=x-20+2/3x+40/3
4/3x+80/3=x-20+2/3x+40/3 /*3
4x+80=3x-60+2x+40
-x=-100 /*(-1)
x=100