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jadi x2+x-12=0
(x+4) atau (x-3) =0
x+4=0 atau x-3=0
x1=-4 atau x2=3
HP{-4,3}
b.disamakan dulu penyebutnya dikali 3
jadi x2+x-12=0
(x+4) atau (x-3) =0
x+4=0 atau x-3=0
x1=-4 atau x2=3
HP{-4,3}