Question

3(x-2)(x+2)-5(x+4)=7

Answer 1

3(x^2+2x-2x-4)-5x-20=7

3x^2+6x-6x-12-5x-20-7=0

3x^2-5x-39=0

delta=25-4*3*-39

delta=493

√ delta = √ 493

x1 =( 5- √ 493)/9

x2 =(5+ √ 493)/9