Odpowiedź:
A) 100°+ALFA+3ALFA=180°
100°+4ALFA=180°
4ALFA=180°-100°
4ALFA=80°
ALFA=80°÷4
ALFA=20°
3ALFA=60°
B)
a+2a-4=11
3a-4=11
3a=11+4
3a=15
a=15÷3
a=5
A)
Trojkat ma 180°
Więc
180°-100°=4a
4a to 80°
80°:4=20°
a=20°
3a=20×3=60°
11=a+2a-4
11+4=3a
15=3a
a=15:3
Pozdrawiam!
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Odpowiedź:
A) 100°+ALFA+3ALFA=180°
100°+4ALFA=180°
4ALFA=180°-100°
4ALFA=80°
ALFA=80°÷4
ALFA=20°
3ALFA=60°
B)
a+2a-4=11
3a-4=11
3a=11+4
3a=15
a=15÷3
a=5
Odpowiedź:
A)
Trojkat ma 180°
Więc
180°-100°=4a
4a to 80°
80°:4=20°
a=20°
3a=20×3=60°
B)
11=a+2a-4
11+4=3a
15=3a
a=15:3
a=5
Pozdrawiam!