proszę o pomoc. wyznacz r z równania
36:pi2=4/3pi*r3
36:pi2=4/3pi*r3 /*3/4
27
-- = pi*r3/:pi
pi2
--- =r3
pi3
3
r=V27/pi3- pierwiastek sześcienny (27/pi3)
r=3/pi
36 : π² =4/3 π *r³ /*π²
36 = 4/3 π * r³ * π² /*3/4
36 * 3/4 = π³ * r³
27 = (π * r)³
3³ = (π * r)³
π * r = 3
r = 3 / π
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36:pi2=4/3pi*r3 /*3/4
27
-- = pi*r3/:pi
pi2
27
--- =r3
pi3
3
r=V27/pi3- pierwiastek sześcienny (27/pi3)
r=3/pi
36 : π² =4/3 π *r³ /*π²
36 = 4/3 π * r³ * π² /*3/4
36 * 3/4 = π³ * r³
27 = (π * r)³
3³ = (π * r)³
π * r = 3
r = 3 / π