Question

"Mnożenie jednomianów przez sumy algebraiczne..."

Rozwiąż:

a) 1/2 (2n-4n) + 1/3 (3m+9n) =

b) 3/4 (m-n) - 1/8 (m+n) =

c) 7/12 (1/7m + 4/21n) + 9/10 (1/3m - 5/6n) =

d) 1/18 (3/2m - 9/4n) - 1/32 (4/3m - 8n) =

e) 0,1 (4x - 5y) - 0,2 (3x + 4y) =

f) 1,1 (1,1x - 1,2y) + 1,2 (1,2x + 1,1y) =

Proszę o pomoc! :)

Answer 1

A) =n-2n+m+3n=2n+m b)=3/4m- 3/4n - 1/8m +1/8n=6/8m -6/8n - 1/8m +1/8n=5/8m - 5/8n c)=1/12m +1/9n+3/10m-3/4n=5/60m+18/60m+4/36n-27/36n=23/60m+23/36n d)=1/12m-1/8n-1/24m+1/4n=1/24m-1/8n e)= 0,4x-0,5y-0,6x-0,8y=-0,2x-1,3y f)=1,21x-1,32y+1,44x+1,32y=2,65x