oblicz 30% wyrażenia 1,5+(2/3-3,6x5/12)/(-1/3)2
to 2 na końcu to potęga o (-1/3)
1,5+(2/3-3,6x5/12)/(-1/3)2 =
= 1,5+(2/3-36/10x5/12)/(-1/9)=
= 1,5+(2/3-180/120)/(-1/9)=
=1,5+(352/120)/(-1/9) =
=1,5+3168/120=
= 1,5+26,4=
= 27,9
[tex]={ 0,3 [1,5 + (2/3 - 3/2 *5/12)/-2/3](do potęgi 2)}- 1/3 ={ 0,3 [1,5 + (2/3 - 3/2 *5/12)/-2/3](do potęgi 2)}- 1/3 ={0,3 [3/2 + -5/6/-2/3] ={ 0,3 [1,5 + (2/3 - 3/2 *5/12)/-2/3](do potęgi 2)}- 1/3 ={0,3[ 9-5/6* (-2/3)] (do potęgi 2)} - 1/3 ={0,3[ 4/6* 4/25] (do potęgi 2) } -1/3+
Proszę
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1,5+(2/3-3,6x5/12)/(-1/3)2 =
= 1,5+(2/3-36/10x5/12)/(-1/9)=
= 1,5+(2/3-180/120)/(-1/9)=
=1,5+(352/120)/(-1/9) =
=1,5+3168/120=
= 1,5+26,4=
= 27,9
[tex]={ 0,3 [1,5 + (2/3 - 3/2 *5/12)/-2/3](do potęgi 2)}- 1/3 ={ 0,3 [1,5 + (2/3 - 3/2 *5/12)/-2/3](do potęgi 2)}- 1/3 ={0,3 [3/2 + -5/6/-2/3] ={ 0,3 [1,5 + (2/3 - 3/2 *5/12)/-2/3](do potęgi 2)}- 1/3 ={0,3[ 9-5/6* (-2/3)] (do potęgi 2)} - 1/3 ={0,3[ 4/6* 4/25] (do potęgi 2) } -1/3+
Proszę