Question

Legenda - () tu należy wpisac potęge? 1,2,3 itp nie ogarniam xd

A1 Zapisz w postaci potęgi

a) 10 x 10 x 10 = 10()
b) 7x7x7 = ()
c) (-9)x (-9) x (-9) = ()
d) 0.8 x 0.8 x 0.8 x 0.8 =()
e) 8= ()
f) (1/5)x(1/5)x(1/5)x(1/5)x(1/5)x(1/5) = ()

A2 uzupełnij 2()=16

b) 3()=27
c0 8()=8
d) do drugiej potęgi = 4
e) do drugiej potegi = 9
f) do 4 potęgi = 256
g 17()=1

h) 5()=625
i (1/2) () = 1/4

B1
Zapisz iloczyny uzywajac poteg
a) 2x2x2x3x3x3
(-4) x (-4) x3 x3 x(-4)=
(-2) x 1/2 x (-2) x 1/2
5x3x3x5x2x5
(1 i 1/3)x (1 i 1/3 )x (4/3)x (4/3)x (4/3) =

Answer 1

A1 

a) 10 x 10 x 10 = 10³
b) 7x7x7 =  7³
c) (-9)x (-9) x (-9) = (-9)³
d) 0.8 x 0.8 x 0.8 x 0.8 =(0,8)⁴
e) 8= (8)¹
f) (1/5)x(1/5)x(1/5)x(1/5)x(1/5)x(1/5) = (1/5)⁶

A2

2⁴=16

b) 3³=27
c) 8¹=8
d) 2²= 4
e) 3² = 9
f) 4⁴ = 256
g 17⁰=1

h) 5⁴=625
i (1/2)² = 1/4 

B1

a) 2x2x2x3x3x3=2³*3³
(-4) x (-4) x3 x3 x(-4)=(-4)³*3²
(-2) x 1/2 x (-2) x 1/2=(-2)²*(1/2)²
5x3x3x5x2x5=2¹*3²*5³
(1 i 1/3)x (1 i 1/3 )x (4/3)x (4/3)x (4/3) = (4/3)⁵

Answer 2

A1  Zapisz w postaci potęgi
a) 10x10x10=10^3
b) 7x7x7=7^3
c) (-9)x(-9)x(-9)=(-9)^3
d) 0.8x0.8x0.8x0.8=0.8^4
e) 8=8^1=2^3
f) (1/5)x(1/5)x(1/5)x(1/5)x(1/5)x(1/5) =(1/5)^6=5^(-6)

A2 uzupełnij

a) 2^4=16

b) 3^3=27
c) 8^1=8
d) 2^2=4
e) 3^2=9
f) 4^4= 256
g 17^0=1

h) 5^4=625
i) (1/2)^2= 1/4
B1
Zapisz iloczyny uzywajac poteg
a) 2x2x2x3x3x3=2^3*3^3
(-4)x(-4)x3x3x(-4)=(-4)^3*3^2
(-2)x1/2x(-2)x1/2=(-2)^2*(1/2)^2
5x3x3x5x2x5=5^3*3^2*2
(1i1/3)x(1i1/3 )x(4/3)x(4/3)x(4/3)=(4/3)^5