1. Od sumy ułamków 3 3/4 i 1 1/3 odejmij różnicę ułamków 2 1/2 i 5 5/6 . 2.Od sumy 10 odejmij sumę ułamków 2.5 i 2/3
1. (3 3/4 + 1 1/3) - (2 1/2 - 5 5/6) = (3 9/12 + 1 4/12) - (2 3/6 - 5 5/6) = 5 1/12 - (-3 2/6) = 5 1/12 - (-3 4/12) = 8 5/12
2. 10 - (2,5 + 2/3) = 10 - (2 3/6 + 4/6) = 10 - 3 1/6 = 6 5/6
Dasz naj?
Mam 5 z matmy
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1. (3 3/4 + 1 1/3) - (2 1/2 - 5 5/6) = (3 9/12 + 1 4/12) - (2 3/6 - 5 5/6) = 5 1/12 - (-3 2/6) = 5 1/12 - (-3 4/12) = 8 5/12
2. 10 - (2,5 + 2/3) = 10 - (2 3/6 + 4/6) = 10 - 3 1/6 = 6 5/6
Dasz naj?
Mam 5 z matmy