Question

(Sec p/6 + cot p/3) / tan p/3

Answer 1

Ga bingung kan ???????????????

Answer 2

Bab Trigonometri
Matematika SMA Kelas X

⇔ [sec π/6 + cot π/3] / tan π/3

⇔ = { [1/(cos 30°)] + [1/(tan 60°)] } / tan 60°

⇔ = { [1/(√3/2)] + [1/√3] } / √3

⇔ = [ 2/√3 + 1/√3 ] / √3

⇔ = [3/√3] / √3

⇔ = 3/3

∴ = 1