Question

Persamaan garis yang melalui titik a(2,-3) dengan gradien 2/3

Answer 1

  y - y₁ = m(x - x₁)
y - (-3) = 2/3(x - 2)
  y + 3 = 2/3x - 4/3
3y + 9 = 2x - 4
     3y = 2x - 4 - 9
     3y = 2x - 13

Answer 2

Persamaan garis : y - y1 = m(x-x1)
y - (-3) = 2/3 (x-2)
y+3 = 2/3 (x-2)
3(y+3) = 2(x-2)
3y+9 = 2x-4
didapat: 2x-3y-4-9 = 0 -----> 2x-3y-13 = 0
atau 2x-y = 13
atau y = 2x-13