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Zad 49
a) √3(√12-2√48-4√27)=
√3(√12-4√12-12√3)=
√3(-3√12-12√3)=
√3(-6√3-12√3)=
√3(-18√3)=
-18√9=-54
b)(√80+√500-4√4500)÷√5=
(2√20+2√125-8√1125)÷√5=
(4√5+10√5-16√225)÷√5=
(4√5+10√5-16·15)÷√5=
(14√5-240)÷√5=14-240=-226