Question

1. 1/3(2y+1)<1/3(5y-1)
2. 7y>5y+4
3. 4x-2<2x+5
4. -2≤x+3≤5
5. 4(y-5)<2(4-3y)+2

Answer 1

1. (2y+1)/3 < (5y - 1)/3. kedua ruas dikali 3, maka:
2y + 1 < 5y -1
2y - 5y < -1 -1
-3y < -2, kedua ruas di kali (-1)
3y> 2
y > 2/3
2. 7y - 5y > 4
2y > 4
y > 4/2
Y > 2
3. 4x - 2x < 5 + 2
2x < 7
x < 7/2
4. X + 3 + 2 ≤ 5
x ≤ 5 - 5
x ≤ 0
5. 4y - 20 < 8 - 6y + 2
4y + 6y < 10 + 20
10y < 30
y < 3