3√5+√50-√72+2√20=
³√3-³√24-³√2+³√16=
Pomóżcie plis
a)3√5+√50-√72+2√20= 3√5 + √2*25 + √2*36 + 2√4*5 = 3√5 + 5√2 -6√2 + 4√5 = 7√5 - √2
b) ³√3-³√24-³√2+³√16= ³√3 - ³√3*8 - ³√2 + ³√2*8 = ³√3 - 2³√3 - ³√2 + 2³√2 = -³√3 + ³√2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)3√5+√50-√72+2√20= 3√5 + √2*25 + √2*36 + 2√4*5 = 3√5 + 5√2 -6√2 + 4√5 = 7√5 - √2
b) ³√3-³√24-³√2+³√16= ³√3 - ³√3*8 - ³√2 + ³√2*8 = ³√3 - 2³√3 - ³√2 + 2³√2 = -³√3 + ³√2