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a5=a1+4r
a12=a1+11r
podstawiam
10=a1+4r(-1)
31=a1+11r
-10=-a1-4r
31=a1+11r
21=7r
r=3
10=a1+4*3
a1=-2
3
log1/3 243 =-5 bo 1/3do potęgi -5 =243
log2√2 64=4 bo 2√2do potęgi 4 = 64
log√5 1/125= -6 bo √5do potęgi -6=125
4
log50-log2=log50/2=log25
czyli log125/log25=log 25 125 =3/2