Question

Znajdz okresy rozwiniec dziesietnych ulamkow.

a)1/6,7/9,7/12,15/22,17/39

b)23/18,19/15,37/22,89/24,170/33

Answer 1

a)

1/6 = 1 : 6 = 0,16666666... = 0,1(6)

7/9 = 7 : 9 = 0,77777777... = 0,(7)

7/12 = 7 : 12 = 0,5833333... = 0,58(3)

15/22 = 15 : 22 = 0,681818181... = 0,6(81)

17/39 = 17 : 39 = 0,435897435897... = 0,(435897)

b)

23/18 = 23 : 18 = 1,27777777... = 1,2(7)

19/15 = 19 : 15 = 1,26666666... = 1,2(6)

37/22 = 37 : 22 = 1,681818181... = 1,6(81)

89/24 = 89 : 24 = 3,708333333... = 3,708(3)

170/33 = 170 : 33 = 5,15151515... = 5,(15)

Answer 2

a) 1/6= 0,1666...

7/9= 0,777...

7/12= 0,58333...

15/22= 0,681818...

17/39= 0,4358974

 

b) 23/18= 1,2777...

19/15= 1,2666...

37/22= 1,681818...

89/24= 3,708333...

170/33= 5,1515...