Wykonaj działania:
a) 4(x+3) =
8(y+4) =
5(-2a+b) =
-4(5y-z) =
b) 0,2(10x-y)*0,4 =
(-0,5y+9)*0,8=
(-2a+4b)*(-1,5) =
c) 1/5(10x+2,5)-0,4=
1/3(3y-2,7)=
-2/3(3,6a-1,5b)=
Wiem, jest tego trochę, ale bardzo prosze o pomoc ;)
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a) 4(x+3)=4x+12
8(y+4)=8y+32
5(-2a+b) =-10a+5b
-4(5y-z) =-20y+4z
b) 0,2(10x-y)*0,4 =0,8x-0,08y
(-0,5y+9)*0,8=-0,4y+7,2
(-2a+4b)*(-1,5) =3a-6b
c) 1/5(10x+2,5)-0,4=2x+0,5-0,4=2x+0,1
1/3(3y-2,7)=y-0,9
-2/3(3,6a-1,5b)=-2,4a+1b
a) 4x+12
8y+32
-10a+5b
-20y+4z
b) 2x-0,2*0,4=0,4x+0,8
0,4y+7,2
3a+6b
c)2x+0,5-0,4=2x+0,1
y-0,9
2,4a+b
prosze :P