Question

33)
√3sin-cosx=√2
Bardzo proszę

Answer 1

Sin(x-y)=sinx*cosy-siny*cosx
√3*sinx-cosx=√2
2*cos(π/6)*sinx-2sin(π/6)*cosx=√2  /:2
sin(x-π/6)=√2/2
x-π/6=π/4+2kπ  v  x-π/6=3π/4+2kπ   /+π/6  , k∈C
x=5π/12+2kπ  v  x=11π/12 +2kπ