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(v+9)(t-2/3)=180
v=180/t
[180/t+9](t-2/3)=180
180-120/t+9t-6=180
9t -120/t-6-0 /*t
9t²-6t-120=0 /;3
3t²-2t-40=0
Δ=4+480=484 √Δ=22
t1=[2-22]/6= sprzeczne bo czas to liczba dodatnia
t=[2+22]/6=4
v=180/4=45
odp.
t=4
v=45