Question

Rozwiąż równania:

2(x+1)^2-6x(x-2)=-1-(3-2x)^2

15(1/3x-3,4)=16(1/4x-5,5)

12(15+x)+4=2(x-12)+38

x-5/2+8-3/3=0

2(2x-22,5)=3(18+x)

8(2x-3)=14(12+x)

Answer 1

= 2*x^2+2*x*1+1^2-6x*(x-2)=-1-3^2-2*3*2x+(2x)^2 ||| 2x^2+2x+1-6x^2-12x=-1-9-12x+4x^2 ||| -4x^2-10x+12x-4x=-10-1 ||| -4x^2-26x=-11 ||| -30x=-11/:-30 ||| x=2,7 |||

Answer 2

2(x+1)²-6x(x-2)=-1-(3-2x)²

2(x²+2x+1)-6x²+12x=-1-(9-12x+4x²)

2x²+4x+2-6x²+12x=-1-9+12x-4x²

-4x²+16x+2=-10+12x-4x²

-4x²+4x²+16x-12x=-10-2

4x=-12/:4

x=-3

 

15(1/3x-3,4)=16(1/4x-5,5)

15/3x-51=16/4x-88

5x-51=4x-88

5x-4x=-88+51

x=-37

 

12(15+x)+4=2(x-12)+38

60+12x+4=2x-24+36

12x+64=2x+12

12x-2x=12-64

10x=-52/:10

x=-5,2

 

x-5/2+8-3/3=0

x-2,5+8-1=0

x+4,5=0

x=-4,5

 

2(2x-22,5)=3(18+x)

4x-45=54+3x

4x-3x=54+45

x=99

 

8(2x-3)=14(12+x)
16x-24=168+14x

16x-14x=168+24

2x=192/:2

x=96