3 . Zapisz w postaci jak najprostrzej sumy algebraicznej :
a) - ( k+3) * ( 2k + 4 )
b) -3 ( a+2b) * ( a-b) +
a) 2k2 - (k+3) * (2k + 4) = 2k2 - (2k2 + 4k + 6k + 12) = 10k + 12
b) -3(a+2b) * (a-b) + 3a2 = (-3a - 6b) * (a-b) - 3a2 = -3a2 + 3ab - 6ba + 6b2 + 3ab = -3a2 + 6b2
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a) 2k2 - (k+3) * (2k + 4) = 2k2 - (2k2 + 4k + 6k + 12) = 10k + 12
b) -3(a+2b) * (a-b) + 3a2 = (-3a - 6b) * (a-b) - 3a2 = -3a2 + 3ab - 6ba + 6b2 + 3ab = -3a2 + 6b2