February 2019 0 32 Report
Para liczb x= -1 y=1 jest rozwiązaniem układu
a) (2-x)kwadrat=(2-y)kwadrat
(x+y)kwadrat=0
b) x+y=0
(x+y)*(x-y)=(x+1)kwadrat
c) x-0,5 + y+0,5=2/3
x kwadrat- y kwadrat=(x+y)(x-y)
d)x+y=2
(x+y)kwadrat=x kwadrat - y kwadrat
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