MATeMAtyka 1 zadanie 5/48 Potęga o wykładniku wymiernym a) 8^-43 x 16 b) 27^-2/3 x 3^4 ...
a)
b)
a) 8^-43 x 16= (2^3)^(-43) x 2^4 = 2^(-129) x 2^4 = 2^(-129 + 4) = 2^(-125)
b) 27^-2/3 x 3^4 = (3^3)^(-2/3) x 3^4 = 3^(-2) x 3^4 = 3^(-2 + 4) = 3^2
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a)
b)
a) 8^-43 x 16= (2^3)^(-43) x 2^4 = 2^(-129) x 2^4 = 2^(-129 + 4) = 2^(-125)
b) 27^-2/3 x 3^4 = (3^3)^(-2/3) x 3^4 = 3^(-2) x 3^4 = 3^(-2 + 4) = 3^2