Question

Rozwiąż równania :

-7(x^2-16)*(x+3)=0

1/2(x+1/3*(x-4)-x=0

x^2 - z do potęgi 2

1/2 , 1/3- ułemek ;D

Proszę o pomoc !!

Answer 1

-7(x^2-16)*(x+3)=0

-7(x - 4)*(x  +4)* (x + 3) = 0

x - 4 = 0 lub x + 4 = 0 lub x + 3 = 0

x = 4 lub x = -4 lub x = -3

1/2(x+1/3)*(x-4) - x=0 ---- / * 6

3(x + 1/3)*(x  -4) - 6x = 0

(3x + 1)*(x - 4) - 6x = 0

3x² - 12x + x - 4 - 6x = 0

3x² - 17x - 4 = 0

Δ = b² - 4ac = 289 + 48 = 337

√Δ = √337

x1 = (17 - √337) / 6 

x2 = (17 + √337) / 6 

Answer 2

-7(x²-16)(x+3)=0

-7(x-4)(x+4)(x+3)

x-4=0 ∨ x+4=0 ∨ x+3=0

x=4 ∨ x=-4    ∨ x=-3

 

½(x+⅓(x-4) -x = 0   

½(x+⅓x-4/3)-x=0

½x+¹/₆x² -⅔ -x =0    /·6

3x+x²-4-6x =0

x²-3x -4=0

Δ=b²-4ac=-3²-4·(-1)·(-4)=25

√Δ=√25=5

x₁=-(-3)-5/ (2·1)=-1

x₂=-(-3)+5/2 =8/2=4