Question

Rozwiąż równanie :
a) 12y - (y+5)= 10y - 1
b) 2(u-5)+15 = 3(u- 4)+ 10
c)-3 (y/3 (to jest ułamek xP) +1 ) - 2 =4(1- y)
d) 2(3a - 2) - 6 = 4,5(2a - 1) +½

Answer 1

A) 12y - (y+5)= 10y - 1
12y - y - 5 = 10y -1
12y - y -10y = 5 - 1
y = 4

b) 2(u-5)+15 = 3(u- 4)+ 10
2u - 10 + 15 = 3u - 12 + 10
2u - 3u = -12 + 10 + 10 - 15
-u = -7
u = 7

c)-3 (y/3 +1 ) - 2 =4(1- y)
-y - 3 - 2 = 4 - 4y
4y - y = 9
3y = 9
y = 3

d) 2(3a - 2) - 6 = 4,5(2a - 1) +½
6a - 4 - 6 = 9a - 4,5 + 0,5
6a - 9a = -4,5 + 0,5 + 4 + 6
-3a = 6
a = -2