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a²+b²+c²=116
(2k)²+(3k)²+(4k)²=116
4k²+9k²+16k²=116
29k²=116
k²=4
k=2
a=2k=2x2=4
b=3k=3x2=6
c=4k=4x2=8
Nos pide el menor
entonces la respuesta seria 4