Question

^3 log 5=p, nilai dari ^25 log 81

Answer 1

Answer 2

Log 5 = p . log 3

^5^{2} log 9^{2}
=> ^5 log 9
=> log 9 per log 5
=> log 9 per (p . log 3)
=> 2 . log 3 per (p . log 3)
=> { log 3 x (2) } per {log 3 x (p)}
=> 2 per p