Question

^2 log 3 = x dan ^2 log 10 = y, nilai ^6 log 120

Answer 1

Log 3 = x . log 2
log 10 = y . log 2

6 log 120 => log 120 per log 6
=> log (10 x 3 x 4) per log (2x3)
=> y . log 2 + x . log 2 + log 4 per log 2 + x . log 2
=> Log 2 (y + x + log 2) per log 2 (1 + x)
=> (y + x + log 2) per (1 + x)