Wiedząc,że sin alfa=2/3 i ctg alfa<0, oblicz: a) sin(pi-alfa)
sin(π-α)=sinα jezeli ctgα<0 i sinα>0, to α∈II cwiartki
sinα=2/3
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sin(π-α)=sinα jezeli ctgα<0 i sinα>0, to α∈II cwiartki
sinα=2/3