cos θ = -1 / 3
secθ = 1/cosθ = -3
sinθ positif di kuadran 2
sinθ = √(3²-1²)/3
sinθ = √8/3
sinθ = 2√2/3
cscθ = 1/sinθ = 3/√8
cscθ = 3/8 √8
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
Diberikan Cos teta=-1/3 dan teta adalah sudut di kuadran kedua. Nilai Sec teta dan Csc teta adalah..?
____________________________
Jawaban :
Misalkan :
Cos teta=-1/3=x/r
x=1
r=3
y=√z²-y²
y=√3²-1²
y=√9-1
y=√8
teta berada dikuadran dua,maka nilai yang + yaitu Sin dan Csc.
Sec teta=r/x=-3/1=-3
Csc teta=r/y=3/√8=3/8√8
________________________
DETIL JAWABAN :
Mapel : Matematika
Kelas : 10
Bab : Trigonometri
Kode : 10.3.4
cos θ = -1 / 3
secθ = 1/cosθ = -3
sinθ positif di kuadran 2
sinθ = √(3²-1²)/3
sinθ = √8/3
sinθ = 2√2/3
cscθ = 1/sinθ = 3/√8
cscθ = 3/8 √8