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1\9+cos²α=1
cos²α=9\9-1\9
cos²α=8\9 /√
cos²α=√8 \3
cosα=2√2\3 tgα=1 \2√2 ctgα=2√2 (odwrotność tg-esu)
c) tgα=3
1²+3²=c²
10=c² /√
c=√10
ctgα=1\3 sinα=3\√10 * √10\√10=3√10\10 cosα=1\√10 * √10\√10=
=√10\10
b) nie wiem o co chodzi