1/3 +4/3 +...25/3 =(1+4+...+25)/3
1+4+...+25
a_1 =1
r=3
a_n =25
zatem: 117/3=39
2.
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1/3 +4/3 +...25/3 =(1+4+...+25)/3
1+4+...+25
a_1 =1
r=3
a_n =25
zatem: 117/3=39
2.