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cos7x = cos5x
7x=5x+2kπ ∨ 7x=-5x+2kπ
2x=2kπ ∨ 12x=2kπ
x1=kπ x2=k·π/6
x∈x2
ODP x=k·π/6
sinx - sin(x-π/3) = 0 zakladam ze jest pomylka
sinx = sin(x-π/3)
x=x-π/3+2kπ ∨ x=π-(x-π/3)+2kπ
sprzecznosc ∨ 2x=4/3π+2Kπ
x=2/3π+kπ
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