Question

Zamień iloczyny na sumy:

a) 3(2x-3y)=

-2(3a+b)=

1/2(4x+2y)=

0,4(5a+10)=

b) 2x(x+2)=

-2x (2)do potegi drugiej)(x - 3y)=

-3x(z+y)=

-3y(-2x+y)=

c) 2(x+1/2)=

5(1/5y-1)=

x(x+y)

5x(2x-y)

d) 6(x+4y-5z)=

-8x(x-y+1)=

x(x(2)do potegi drugiej) -2x-1)=

1/2x(y-z+1)=

Answer 1

a) 6x - 9y

-6a -2b

2x + y

2a + 4

 

b) 2x^2 + 4x

-2x[2^2(x-3y)] = -2x[4(x-3y)] = -2x(2x-12y)=4x^2-24xy

-3xz - 3xy

6xy - 3y^2

 

c)2x + 1

y-5

x^2+xy

10x^2-5xy

 

d) 6x+24y-30z

-8x^2+8xy-8x

x[2^2x-2x-1] = x(4x-2x-1) = x(2x-1)=2x^2-x

1/2xy-1/2xz+1/2x