Oblicz wartość liczbową wyrażenia algebraicznego po uproszczeniu.
a) 5ab + 3ab = a=7
4a b=-2
b) 2(a+b-1) - 3(a-b) = a=-1
3 b= 1/2
c) -3x(2-4x) + (-2x-7) - 1/2(x+8)= x= -3
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a)
5ab + 3ab = 8ab = b = -2
4a 4a
b)
2(a+b-1) - 3(a-b) = 2a +2b - 2 - 3a - 3b = -a - b - 2 = 1 - 1/2 - 1 = -1/6
3 3 3 3
c)
-3x(2-4x) + (-2x-7) - 1/2(x+8)= -6x+12x(kwadrat) - 2x-7-1/2x+4= -8x - 1/2x -3 - 12x(kwadrat) =
= 24 + 1,5 -3 + 108 = 130,5
a) a = 7 b = - 2
=\frac{8ab}{4a}=\frac{8 * 7 * (-2) }{4*7}=\frac{-112}{28}=-4
b)a= -1 b = \frac{1}{2}
\frac{2(a+b-1) - 3(a-b)}{3}=\frac{2(-1+\frac{1}{2}-1)-3(-1-\frac{1}{2}}{3}=\frac{2(-1\frac{1}{2}-3(-1\frac{1}{2}){3}=\frac{2 * (-\frac{3}{2})-3*(-\frac{3}{2})}{3}=\frac{-3+\frac{9}{2}}{3})=\frac{-\frac{6}{2}+\frac{9}{2}}{3}=\frac{\frac{3}{2}}{3})=\frac{3}{2}*\frac{1}{3})=\frac{1}{2}
c) x = - 3
-3 * (-3)(2-4*(-3)) + (-2 * (-3) -7) - \frac{1}{2}(-3 +8)=9(2+12) +(6-7) -\frac{1}{2}(5)=9*14+ (-1) - 2,5= 122,5