chyba tak ale pewności niemam -8x+12 iten znaczek
a)
f(x) = x-6
x-6 = 0
x = 6
b) f(x) = 2x+1
2x+1 = 0
2x = -1
x = -1/2
c)
f(x) = 6x-3
6x-3 = 0
x = 1/2
d)
f(x) = -8x+12
-8x = -12 |:-8
x = 2/3
e)
f(x)= -1/2x+5
-1/2x = -5 |*-2
x = 10
f)
f(x)=0,01x-50
0,01x = 50 |*100
x = 5000
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chyba tak ale pewności niemam -8x+12 iten znaczek
a)
f(x) = x-6
x-6 = 0
x = 6
b) f(x) = 2x+1
2x+1 = 0
2x = -1
x = -1/2
c)
f(x) = 6x-3
6x-3 = 0
x = 1/2
d)
f(x) = -8x+12
-8x = -12 |:-8
x = 2/3
e)
f(x)= -1/2x+5
-1/2x = -5 |*-2
x = 10
f)
f(x)=0,01x-50
0,01x = 50 |*100
x = 5000