2x^4-13x^2+6=0
Rozwiąż równanie.
2x⁴ - 13x² + 6= 0
niech x² = a
2a² - 13a + 6
Δ = (-13)² - 4*2*6 = 121
√Δ = √121 = 11
a₁ = -(-13)-11/2*2 = 0,5
a₂ = -(-13)+11/2*2 = 6
x² = 0,5 lub x² = 6
x = -√2/2 lub x = √2/2 lub x = √6 lub x = -√6
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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2x⁴ - 13x² + 6= 0
niech x² = a
2a² - 13a + 6
Δ = (-13)² - 4*2*6 = 121
√Δ = √121 = 11
a₁ = -(-13)-11/2*2 = 0,5
a₂ = -(-13)+11/2*2 = 6
x² = 0,5 lub x² = 6
x = -√2/2 lub x = √2/2 lub x = √6 lub x = -√6
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)