Question

Rozwiaz nierownosc:

1/2x^2+x-4<=0

^potega

<= wieksze badz rowne

Answer 1

(1/2)x^2 + x - 4 <= 0 

 

D(delta) = b^2 - 4ac = 1 - 4(1/2)(-4) = 1+8 = 9

VD = V9 = 3

x1 = (-b-VD)/2a

x1 = (-1-3)/(2 *1/2) = -4

x2 = (-b+VD)/2a

x2 = (-1+3)/(2 *1/2) = 2

 

a > 0, 

ramiona paraboli skierowane w górę,

 

xe <-4, 2>