Rozwiąż równania. g)3/4(2-3x)=-6 i)0,6+x/2=x+1 prosze o pomoc
g)3/4(2-3x)=-6
a więc : ¾*2 - ¾*3x = -6
1.5- 2¼x = -6 / -1.5
-2¼x=-7.5 /:-2¼
x= 3⅓
i)0,6+x/2=x+1 /*2
a więc : 2(0,6 + x/2) = 2(x+1)
1,2 + x = 2x + 2 / - 2
-0,8 + x = 2x /-x
x = -0,8
g)
3/4(2-3x)=-6
0,75(2-3x)=-6
1,5-2,25x=-6
-2,25x=-6-1,5
-2,25x=-7,5 |:(-2,25)
x=3,3
i)
0,6+x/2=x+1 |*2
1,2+x=2x+2
x-2x=2-1,2
-x=0,8 |:(-1)
x=-0,8
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g)3/4(2-3x)=-6
a więc : ¾*2 - ¾*3x = -6
1.5- 2¼x = -6 / -1.5
-2¼x=-7.5 /:-2¼
x= 3⅓
i)0,6+x/2=x+1 /*2
a więc : 2(0,6 + x/2) = 2(x+1)
1,2 + x = 2x + 2 / - 2
-0,8 + x = 2x /-x
x = -0,8
g)
3/4(2-3x)=-6
0,75(2-3x)=-6
1,5-2,25x=-6
-2,25x=-6-1,5
-2,25x=-7,5 |:(-2,25)
x=3,3
i)
0,6+x/2=x+1 |*2
1,2+x=2x+2
x-2x=2-1,2
-x=0,8 |:(-1)
x=-0,8