prosze pomocy na dzisiaj rozwiąż równania 6[1-1/3x]=2[1x+1/2x]
0.3x-2[0.1x+1]=0
0.5[x-3]+0.25[2x+6]=5
-x-3=x-4
1) 6(1-1/3x) = 2(1x+1/2x)
6-2x = 2x+x
6 = 2x+x+2x
6 = 5x /:5
1,2 = x
2) 0.3x-2[0.1x+1]=0
0.3x-0.2x-2 = 0
0.1x = 2 / 0.1
x = 20
3) 0.5[x-3]+0.25[2x+6]=5
0.5x-1.5+0.5x+1.5 = 5
x = 5+1.5-1.5
x= 5
4) -x-3=x-4
-3+4 = x+x
1 = 2x / :2
0.5 = x
Liczę na naj ;)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1) 6(1-1/3x) = 2(1x+1/2x)
6-2x = 2x+x
6 = 2x+x+2x
6 = 5x /:5
1,2 = x
2) 0.3x-2[0.1x+1]=0
0.3x-0.2x-2 = 0
0.1x = 2 / 0.1
x = 20
3) 0.5[x-3]+0.25[2x+6]=5
0.5x-1.5+0.5x+1.5 = 5
x = 5+1.5-1.5
x= 5
4) -x-3=x-4
-3+4 = x+x
1 = 2x / :2
0.5 = x
Liczę na naj ;)