chodzi mi o obliczanie wyrażeń algebraicznych, jestem w 6 kl.
c) 3(x-2)=x, d) 3(2x+3)=3(x+1), f) -(x-1)=2, g) x=1-3(x+1), h) (x+1)-(1-x)=1, j) -1/4(2+x)=3/4x, k) -2(x+1/2)-3(x+1/3)=0, l) (x+2)*6=0,5x, m) 0,1(x+2)=0,2x, n) 6(1-1/3x)=2(1+1/2x(, o) 0,3x-2(0.1x+1)=0 p) 0,5(x-3)+0,25(2x+6)=5
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c) 3(x-2)=x,
3x - 6 = x
3x - x = 6
2x = 6
x = 3
d) 3(2x+3)=3(x+1),
6x + 9 = 3x +3
6x - 3x = 3 - 9
3x = -6
x = -2
f) -(x-1)=2,
-x + 1 = 2
-x = 2 - 1
-x = 1
x = -1
g) x=1-3(x+1),
x = 1 - 3x - 3
x + 3x = -3 + 1
4x = -2
x = -2/4
x = -1/2
h) (x+1)-(1-x)=1,
x +1 - 1 + x = 1
2x = 1
x = 1/2
j) -1/4(2+x)=3/4x,
-(2 +x) = 3x
-2 - x = 3x
-x - 3x = 2
-4x = 2
x = -1/2
k) -2(x+1/2)-3(x+1/3)=0,
-2x - 1 - 3x - 1 = 0
-5x = 2
x = -2/5
l) (x+2)*6=0,5x,
6x + 12 = 0,5x
6x - 0,5x = -12
5,5x = 12
x = 12 : 5 i 1/2
x = 12 : 11/2
x = 12 * 2/11
x = 24/11
x = 2 i 2/11
m) 0,1(x+2)=0,2x,
0,1x + 0,2 = 0,2x
0,1x - 0,2x = -0,2
-0,1x = 0,2
x = 0,2 : (-0,1)
x = -2
n) 6(1-1/3x)=2(1+1/2x(,
6 - 2x = 2 + x
-2x - x = 2 - 6
-3x = -4
x = 4/3
x = 1 i 1/3
o) 0,3x-2(0.1x+1)=0
0,3x - 0,2x - 2 = 0
0,1x = 2
x = 2 : 0,1
x = 20
p) 0,5(x-3)+0,25(2x+6)=5
0,5x - 1,5 + 0,5x + 1,5 = 5
x = 5