Question

Tlng bantuin crnya ya..

1. titik P(p,10) trletak pd garis y=-1/2x +9. mka nilai p adlh...

2. dua titik dngn koordinat (2,6) dan (3,p) dilalui garis yg gradiennya -4, mka nilai p adlh....

Answer 1

1) y = -1/2x + 9 → ttk.P(p,10)
10 = -1/2.p + 9
10 - 9 = -1/2.p
1 = -1/2.p
p = 1 : -1/2
p = 1.(-2)
p = -2




2) gradien (m) = y2-y1/x2-x1
-4 = p-6/3-2
-4 = p-6/1
-4.1 = p-6
-4 = p-6
p = -6+4
p = -2