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|2 sinx-√3|=√3
2 sinx-√3 = -√3
2 sin x = 0
sin x = 0
x = k π oraz k∈ C
2 sinx-√3 = √3
2 sin x = 2√3
sin x = √3
brak rozwiązania, bo √3 >1
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3+4cos(1/2x)=-1
4cos(1/2x) = -4
cos (1/2x) = -1
1/2x = 3/2 π + 2k π
x = 3 π + 4 k π
oraz k ∈ C